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(C) For a mirror,magnification $m = -\frac{v}{u}$.$1. m = -2$: Negative $m$ implies a real and inverted image. Only a concave mirror can produce a rea

Vedclass · Accepted Answer

$(1-b, c), (2-b, c), (3-b, d), (4-a, d)$

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(C) For a mirror,magnification $m = -\frac{v}{u}$.$1. m = -2$: Negative $m$ implies a real and inverted image. Only a concave mirror can produce a real image with magnification $|m| > 1$. Thus,$(1-b, c)$.$2. m = -\frac{1}{2}$: Negative $m$ implies a real and inverted image. $A$ concave mirror can produce a real image with magnification $|m| $3. m = +2$: Positive $m$ implies a virtual and erect image. Only a concave mirror can produce a virtual and magnified image. Thus,$(3-b, d)$.$4. m = +\frac{1}{2}$: Positive $m$ implies a virtual and erect image. Both concave and convex mirrors can produce virtual images,but a convex mirror always produces a diminished virtual image. Thus,$(4-a, d)$ or $(4-b, d)$.Comparing with the options,the correct match is $(1-b, c), (2-b, c), (3-b, d), (4-a, d)$.

Column-$I$	Column-$II$
$1. m = -2$	$a$. Convex mirror
$2. m = -\frac{1}{2}$	$b$. Concave mirror
$3. m = +2$	$c$. Real Image
$4. m = +\frac{1}{2}$	$d$. Virtual image

Match the corresponding entries of Column-$I$ with Column-$II$. [Where $m$ is the magnification produced by the mirror]

Column-$I$ Column-$II$

$1. m = -2$ $a$. Convex mirror

$2. m = -\frac{1}{2}$ $b$. Concave mirror

$3. m = +2$ $c$. Real Image

$4. m = +\frac{1}{2}$ $d$. Virtual image

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Match the corresponding entries of Column-$I$ with Column-$II$. [Where $m$ is the magnification produced by the mirror] Column-$I$ Column-$II$ $1. m = -2$ $a$. Convex mirror $2. m = -\frac{1}{2}$ $b$. Concave mirror $3. m = +2$ $c$. Real Image $4. m = +\frac{1}{2}$ $d$. Virtual image